Math, asked by DHRUVG4469, 6 months ago

11.ABCD is a rectangle and ABEF is a parallelogram and AB||CF. If AB = 10 cm. and BC = 6 cm, find
(i) area of rectangle ABCD
(ii) area of Parallelogram ABEF
(iii) area of BEF

Answers

Answered by jaysoni121019
0

Answer:

Answer:

()= 60sqcm

(i)= 60sqcm

(ii)= 60sqcm

Step-by-step explanation:

()In rectangle ABCD,

AB (length )= 10cm

BC (breadth)= 6cm

Hence,

Area of Rectangle ABCD=length ×breadth

= 10 × 6

= 60sqcm

(i)In Parallelogram ABEF,

AB||CF ... 1) (Given )

AB||EF ... 2)

( Opposite sides of parallelograms are parallel )

Hence, CF||EF From 1) & 2)

hence, BC = BE

i.e. BE = 6 cm

Area of Parallelogram = base ×height

= 10 × 6

= 60 sqcm

(ii) Area of ABEF = 60sqcm

I have a problem that you have not uploaded this with picture if you has done that so I should get clarity.

Anyway,

I think it will help you

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