11. ABCD is a rhombus. Diagonals AC and BD bisect each other at point o such that
AC = 6 cm and BD = 8 cm. Find the side of the rhombus.
Answers
Answered by
17
Answer:
side=5cm
Step-by-step explanation:
DIAGONAL OF RHOMBUS BISECT EACH OTHER AT 90°
Let us consider the bisection point as 'O'
In rhombus ABCD,
AO=3cm
BO=4cm
According to PYTHAGORAS THEORM,
(AO)^2+(BO)^2=(AB)^2
(3)^2+(4)^2=(AB)^2
(AO)^2(BO)^2=(AB)^2
9+16=(AB)^2
√25=(AB)^2
5cm=AB
Therefore the side of rhombus is 5cm
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Answered by
4
Step-by-step explanation:
5 cm
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