Question

11. ABCD is a rhombus. Diagonals AC and BD bisect each other at point o such that
AC = 6 cm and BD = 8 cm. Find the side of the rhombus.

Answer 1

Answer:

side=5cm

Step-by-step explanation:

DIAGONAL OF RHOMBUS BISECT EACH OTHER AT 90°

Let us consider the bisection point as 'O'

In rhombus ABCD,

AO=3cm

BO=4cm

According to PYTHAGORAS THEORM,

(AO)^2+(BO)^2=(AB)^2

(3)^2+(4)^2=(AB)^2

(AO)^2(BO)^2=(AB)^2

9+16=(AB)^2

√25=(AB)^2

5cm=AB

Therefore the side of rhombus is 5cm

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Answer 2

Step-by-step explanation:

5 cm

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