11. ABCD is a trapezium with AB parallel to DC.
If AB = 10 cm, AD = BC = 4 cm and
ZDAB = 2CBA = 60°, calculate
(i) the length of CD;
(ii) the distance between AB and CD. (ICSE)
Answers
Answered by
4
Step-by-step explanation:
in trapezium ABCD
AB||CD. (GIVEN)
AB=10CM
AD=BC=4CM
DAB=CBA=60°
LENGTH OF SIDE CD=10^2+2^2=HYPOTENUSE
100+4=√104=10.2 APPROX
Similar questions