Question

11. An aeroplane leaves an airport and flies due north at a speed of 1000 km per hour. At the
same time, another aeroplane leaves the same airport and flies due west at a speed of
1
hours?
1200 km per hour. How far apart will be the two planes after 1
2
d 11 m stand on a.​

Answer 1

Answer

The first aeroplane leaves an airport and flies due north at a speed of 1000 km per hr.

∴ Distance travelled in 1.5 hrs.

=1000×1.5=1500 km

Similarly, Distance traveled by second aeroplane,

=1200×1.5=1800 km

In △ABC,

BC is distance travelled by first aeroplane and BA is the distance traveled by second aeroplane.

Hence, applying Pythagoras Theorem,

AC  

2

=AB  

2

+BC  

2

 

∴ AC  

2

=1500  

2

+1800  

2

 

∴ AC=300  

61

​  

 km

Hence, two planes are 300  

61

​  

 km apart.