Question

11. An artificial satellite is moving around earth in a circular orbit with speed equal to one fourth the escape speed
of a body from the surface of earth. The height of satellite above earth's surface is (R is radius of earth)
(1) 3R
(2) 5R
(3) 7R
(4) SR​

Answer 1

Explanation:

Escape velocity = √(2gR) Speed of satellite = √(2gR)4 By force balance, GMmx2 = m(√(2gR)4)2x x = GM2gR × 16 = 8 GMgR = 8R Height of satellite ...