Question

11. An electric heater is rated 500 VA, 200 V. If the heater is operated for 1 hour; calculate
the energy consumed (i) in kWh (ii) joule.
[Ans. (i) 0.5 kWh; (ii) 1.8 x 10°]​

Answer 1

Explanation:

Answer:- E = 1,800,000J Or, 1800 KJ

Given :- p = 500 w v = 200v t = 1 h 3600 s

To find :- The energy consumed :-

SOLUTION:- The energy consumed by electric heater is given by :-

\huge \boxed {E = p \times t} E=p×t

Put the given value, →E = 500 \times 3600E=500×3600 →E = 1,800,000 jE=1,800,000j To convert it in to kJ To convert it in to kJ1 KJ = 1000 J →E = \dfrac{1,800,000}{1000}E= 1000 1,800,000 →E = 1800 kJE=1800kJ

hence, The energy consumed is 1800 kJ