Question

11. An electric lamp whose resistance is 20 12 and a conductor of 4 resistance
are connected in series to a 6V battery. Find the current through the circuit and
the potential difference across the electrical lamp and conductor.​

Answer 1

Answer:

a). the total resistance of the circuit =20Ω+4Ω=24Ω

b). The current through the circuit= current through the bulb= current through the conductor.

The current through the circuit=

the voltage of the battery

voltage applied

.

the current through the circuit = 24

6 amp

The current through the circuit = 0.25amp

c). The potential difference across the lamp and the conductor.

(i) The potential difference across the electrical lamp =0.25×20=5volt

(ii) The potential difference conductor =0.25×4=1 volt

d). Power can be calculated as

current through the lamp

voltage across the lamp

power= 0.25

5→20W.

Explanation:

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