Question

11. An electric lamp whose resistance is 20 and a conductor of 4 resistance are
connected in series to a 6V battery. Find the current through the circuit and the
potential difference across the electrical lamp and conductor.​

Answer 1

Answer:

the total resistance of the circuit =20Ω+4Ω=24Ω

b). The current through the circuit= current through the bulb= current through the conductor.

The current through the circuit=

the voltage of the battery

voltage applied

.

the current through the circuit =

24

6

amp

The current through the circuit = 0.25amp

c). The potential difference across the lamp and the conductor.

(i) The potential difference across the electrical lamp =0.25×20=5volt

(ii) The potential difference conductor =0.25×4=1 volt

d). Power can be calculated as

current through the lamp

voltage across the lamp

power=

0.25

5

→20W

Answer 2

Answer:

• An electric lamp whose resistance is 20 ohms and conductors of 4 ohms resistance are connected by to a 6 Volt battery ....
• V1 = IR¹ = 0.25 A × 20 ohms = 5 volt

potential difference across the conductors is V ² = IR2 = 0.25 A× 4 ohms = 1 volt

Explanation:

I hope this helps you