Question

11.An element has bcc structure with a cell edge of 288 pm. the density ot the elemct 7.2 gcm. how many atoms are present in 208g of the element.​

Answer 1

Answer:

2.418 X 10∧24

Explanation:

Number of atoms present in 208 g = No. of atoms per unit cell × No. of unit cells

=2×12.09×10 ^23

=24.18×10 ^23

 =2.418×10 ^24