11. An elevator descends into a mine shaft at the rate of 6 m/min.
10 m above sea level.
(1) Where will it reach in 20 minutes?
(1) How long will it take to reach a depth of -350 m?
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Rate of descends of the elevator =6m/min
Initial position =10m
Final position =-350 m
Total distance descent = 10m - (-350)
=10m +350m
=360m
Therefore time taken=360 divided by 6 = 60 min = 1 hr
(The other question sry I don’t know ...hope this helps u)
Initial position =10m
Final position =-350 m
Total distance descent = 10m - (-350)
=10m +350m
=360m
Therefore time taken=360 divided by 6 = 60 min = 1 hr
(The other question sry I don’t know ...hope this helps u)
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