11. An engine is travelling along a circular railway track of radius 1500 metres with a speed
of 60 km/h. Find the angle in degrees turned by the engine in 10 seconds.
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60km/hr=60×5/18=50÷3 m/s
So in 10 second total distance covered =500÷3 m
Circumference of circular path = 2× π ×1500 =3000π
This means that if the train covered the whole circle ie.360 degrees
We can say that to cover 360 degrees of circle the distance to travel is 3000π
So in 1 degree the train has to cover 3000π÷360 m
but the train covered 500÷3 m
So the degree of the track =distance covered by train ÷ distance per degree
Degree of track = 3000×22/7÷360 ÷ 500/3
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