11. An examination is being held in two parts and there are 572 examinees in all 3/11of the total
number of examinees appears in part I only and 3/13appears in part II only. The rest appear
in both the parts. Find the number of candidates appearing in both the parts.
Answers
Answered by
12
Answer:
284
Step-by-step explanation:
total examiners = 572
no. of students that appear in 1st part
= 3/11×572
=156
no. of students that appear in 2nd part
=3/13×572
=132
total no.of students appearing in 1st and 2nd part together=156+132=288
no.of candidates appearing in both the parts=572-288=284
Answered by
3
Answer:
284
Step-by-step explanation:
Total examineers =572
no of students that appear in 1st part= 3/11×572 =156
no of students that appear in 2nd part = 3/13× 572 = 132
total no of students appearing 1st and 2nd part together = 156 + 132 = 288
No of candidates appearing in both the parts = 572 - 288 = 284 Ans
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