Question

11. An iron nail is kept immersed in copper sulphate solution in a test tube. After sometime, you observe that brown coating is placed on the iron nail. What is your inference from this experiment? a) The brown coating is placed on the iron nail because iron has displaced copper from copper sulphate solution. b) The brown coating is placed on the iron nail because copper has displaced iron. c) The brown coating is placed on the iron nail because copper sulphate solution is usually brown. d) The brown coating is placed on the iron nail because of presence of oxygen sed for​

Answer 1

Answer:

a) the brown coating is placed on the iron nail because iron has displaced copper from copper sulphate solution

I hope this will help you

Answer 2

Answer:

When an iron nail immersed in the solution of copper sulphate than iron displaces copper from the solution of copper sulphate because iron is more reactive than copper. Therefore copper sulphate solution colour changes from blue to pale green.

Reaction

CuSO4 (aq) + Fe (s) → FeSO4 (aq) + Cu (s)

In this reaction following two processes take place:

Cu²⁺ + 2e = Cu⁰ (re­duc­tion process, Cu²⁺ is the ox­i­dizing agent)

Fe⁰ – 2e = Fe²⁺ (ox­i­da­tion process, Fe⁰ is the re­duc­ing agent)

The reaction can be double displacement reaction as well as redox reaction (oxidation and reduction both takes place simultaneously).

Explanation

When an iron nail is dipped in copper sulphate solution, a brown coating of copper is formed in the surface of iron and the colour of copper sulphate solution changes from blue to pale green. The reaction shows that iron is more reactive than copper because it displaces copper from the copper sulphate solution. The iron passes into the solution as Fe (II) forming the ferrous sulphate solution.