Question

11 An object is dropped from a tower 280 m high. How long does it take to reach the
ground? (Take g =10m/s2)
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Answer 1

Answer:

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Answer 2

$s = ut + \frac{1}{2} \times g {t}^{2}$

s=280m t=? u=0

280=0×t+1/2×10t^2

280=5×t^2

t^2=56

$t = \sqrt{56}$

$t = 2\sqrt{14} sec$

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