Question

11. At what time between 10 and 11 o'clock, are the hands 2 min. space apart ?
(A) 52
4 8
& 56
11 11
past 10
(B) 10.55
2
(C) 10.35
(D) 50
11
past 10​

Answer 1

Answer:

Let at xminute past 10 o'clock they become symmetric

We know the Speed of hour hand and minute hand is 1 : 12

∴ When minute handmoves xmimute distance then hour hand moves

12

x

minute distance

∴

12

x

=10−x

⇒

12

13x

=10

⇒x=

13

120

∴x=9 minute 13.8 second therefore required time is 10h 9m 13.8 sec.

Answer 2

Answer:

 Let at xminute past 10 o'clock they become symmetric

We know the Speed of hour hand and minute hand is 1 : 12

∴ When minute handmoves xmimute distance then hour hand moves 12x minute distance

∴12x=10−x

⇒1213x=10

⇒x=13120

∴x=9 minute 13.8 second therefore required time is 10h 9m 13.8 sec.

Explanation:

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