Question

11. Baichung’s father is 26 years younger than Baichung’s grandfather and 29 years older than Baichung. The sum of the ages of all the three is 135 years. What is the age of each one of them?

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Answer 1

Answer:

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Baichung’s father is 26 years younger than Baichung’s grandfather and 29 years older than Baichung. The sum of the ages of all the three is 135 years. What is the age of each one of them?

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$\huge \rm \purple{\dag Let \dag}$

The age of Baichung be x years.

Age of father would be x + 29 years.

Age of grandfather would be x + 29 + 26

= x + 55 years

Now sum of their ages is given to be 135 years.

so,

x + x + 29 + x + 55 = 135

3x + 84= 135

3x = 135 - 84

3x = 51

x = 51/3

$\tt{\underline{\bold{x = 17}}}$

Age of Baichung = 17 years

Age of Baichung's father = 17 + 29 = 46 years

Age of Baichung's grandfather = 17 + 55 = 72 years.

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Answer 2

Given :

• Baichung 's father is 26 years younger than Baichung's grandfather and 29 year older than Baichung .
• The sum of the age of all the three is 135 years.

To Find :

• Age of Baichung , his father and his grandfather .

Solution :

$\longmapsto\tt{Let\:Age\:of\:Grandfather\:be=x}$

As Given that Baichung 's father is 26 years younger than Baichung's grandfather and 29 year older than Baichung .So ,

$\longmapsto\tt{Age\:of\:Baichung's\:Father=x-26}$

$\longmapsto\tt{Age\:of\:Baichung=x-26-29=x-55}$

A.T.Q :

$\longmapsto\tt{x+x-26+x-55=135}$

$\longmapsto\tt{3x-81=135}$

$\longmapsto\tt{3x=135+81}$

$\longmapsto\tt{3x=216}$

$\longmapsto\tt{x=\cancel\dfrac{216}{3}}$

$\purple\longmapsto\:\large\underline{\boxed{\bf\blue{x}\pink{=}\red{72}}}$

Value of x is 72 .

Therefore :

$\longmapsto\tt{Age\:of\:his\:Grandfather=x}$

$\longmapsto\tt\bf{72\:yrs}$

$\longmapsto\tt{Age\:of\:his\:Father=72-26}$

$\longmapsto\tt\bf{46\:yrs}$

$\longmapsto\tt{Age\:of\:Baichung=72-55}$

$\longmapsto\tt\bf{17\:yrs}$