11. Calculate the area of trapezium as shown in thefigure DC=6CM,OA=6CM,BC=17CM,OB=8CM
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Answer: 150cm²
Step-by-step explanation:
OC⊥AB
So OC²=BC²-OB² (Pythagoras Theorem)
OC² = 17²-8² = 289-64 = 225
Therefore OC = 15 cm
ar(Trapezium)= ar(TriangleBOC)+ar(RectangleADCO)
ar(Trapezium) = [1/2×8×15]+[6*15] =60+90=150 cm²
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