Question

(11)
Calculate the force between two Protons, if they are 4.0 × 10-15 meters away from
each other. (Where, charge of Proton is 1.6*10-19 Coulomb.)​

Answer 1

Answer:14.4 Newton

Explanation:

Answer 2

Given :

The charge of proton = 1.6 * 10 ^ (-19) C

The distance between the protons = 4.0 * 10 ^ (-15) m

To find :

The forces between the protons .

Solution :

Force , F = k * q$_1$ * q$_2$ / r * r

where , k is constant equal to 9.0 * 10 ^ 9 N$m^2$ / $C^2$ ,

q$_1$ and q$_2$ are two charges ,

and , r is distance between the charges .

Now ,

F = [ 9.0 * 10^9 * 1.6 * 10^(-19) * 1.6 * 10^(-19)] / [ 4.0 * 10^(-15) * 4.0 * 10^(-15)]

=> F = 14.4 N

The forces between the protons is 14.4 N .