(11)Calculate the force between two Protons, if they are 4.0 × 10-15 meters away fromeach other. (Where, charge of Proton is 1.6*10-19 Coulomb.)
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Given :
The charge of proton = 1.6 * 10 ^ (-19) C
The distance between the protons = 4.0 * 10 ^ (-15) m
To find :
The forces between the protons .
Solution :
Force , F = k * q_1 * q_2 / r * r
where , k is constant equal to 9.0 * 10 ^ 9 Nm^2 / C^2 ,
q_1 and q_2 are two charges ,
and , r is distance between the charges .
Now ,
F = [ 9.0 * 10^9 * 1.6 * 10^(-19) * 1.6 * 10^(-19)] / [ 4.0 * 10^(-15) * 4.0 * 10^(-15)]
=> F = 14.4 N
The forces between the protons is 14.4 N .
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