Question

11.Calculate the no of molecules present in

a) 22.7 L of CO2

b) 3.4 g of NH3
c)18 ml of water ​

Answer 1

Answer:

Mass of 1 mol or (6.022×10

23

molecules) of NH

3

=14+3×1=17 g

Number o f molecules in 34 g NH

3

=

17

34

×6.022×10

23

=12.044×10

23

Number of atoms present in 1 molecule of NH

3

=4

Number of atoms in 34 g NH

3

=4×12.044×10

23

≈48×10

23

Answer 2

Answer:

a) 3106.80×10^23

b) 30.11 × 10^23

c) 6.022×10^23