Question

11. Calculate the number of aluminium ions present in 0.051 g of aluminium oxide.
(Hint: The mass of an ion is the same as that of an atom of the same element. Atomic mass of
Al = 27 u)
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Answer 1

Answer:

Aluminium oxide = Al2O3

in 1 molecule there are 2 Al+3 ions

Molecular weight of Aluminium oxide = 2(27)+3(16)=54+48=102g

hence, 102g molecule contain 54g Al+3

and 0.051g will contain, 54/102 ×0.051 =0.027g Al+3 ions.

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