Question

11) Check whether 6n ending with digit "o"
not?​

Answer 1

Step-by-step explanation:

if any digit has the last digit 10 that means it is divisible by 10

the factor of 10=2×5

so value of 6n should be divisible by 2 and 5

both 6n is divisible by 2 but not divisible by 5

so, it can not end with 0

Answer 2

Step-by-step explanation:

${6}^{n}$

•

${6}^{1} = 6$

${6}^{2 } = 36$

${6}^{3} = 216$

•

•

and etc

therefore,The number

${6}^{n}$

to end with digit 0 it should contain 5 in its prime factorisation

${6}^{n } = (2 \times 3) {}^{n}$

here 2 and 3 are the only primes in

${6}^{n}$

so 6^n cannot end with 0