Math, asked by gandlanaveengandla, 5 months ago

11) Check whether 6n ending with digit "o"
not?​

Answers

Answered by 5253kwbatul
1

Step-by-step explanation:

if any digit has the last digit 10 that means it is divisible by 10

the factor of 10=2×5

so value of 6n should be divisible by 2 and 5

both 6n is divisible by 2 but not divisible by 5

so, it can not end with 0

Answered by Karthikeya061205
0

Step-by-step explanation:

 {6}^{n}

 {6}^{1}  = 6

 {6}^{2 }  = 36

 {6}^{3}  =  216

and etc

therefore,The number

 {6}^{n}

to end with digit 0 it should contain 5 in its prime factorisation

 {6}^{n }  = (2 \times 3) {}^{n}

here 2 and 3 are the only primes in

 {6}^{n}

so 6^n cannot end with 0

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