Question

11. Classify the following data by taking class interval such that their mid-values are 17, 22, 27, 32 and so on: 54 30 15 48 40 42 51 17 30 41 42 25 28 28 36 54 37 42 27 31 44 40 36 30 16 42 22 48 32 31 40 19 21 36 22 30 36 41 37 47 46 52 17 16 53 21 41 33​

Answer 1

Answer:Explanation:

What you provided here is simple data…….17 , 22,  27,  32 ,……

And no other information has been provided by you. If looking at the data, the differene is…

22 – 17 = 5.

27 – 22 = 5.

32 – 27 = 5.

So it is obvious that your so on data would include….32 + 5 = 37 , 37 + 5 = 42, 42 + 5 = 47 and …..

Now we know that the mid values in the given data are…..17 , 22, 27, 32, 37, 42, 47 and so on..

So perfect distribution would be…..as below.

Class-Interval  Mid-Point

15 – 19   17

20 – 24   22

25 – 29   27

30 – 34   32

35  - 39   37 and so on….

Hope that solves your issue.

Explanation: