Question

11
(d) vco (product) = vco (free co)
Arrange the following carbonyl complexes in the descending order of their back bonding:
(1) Crico). (ii) [Ti(CO):1- (iii) (Mn(CO):) (ix) (Ir(CO).] (v) [V(CO):)"
(1) Ir> V>I> III > IV
{b) II > III > IV>V>I
(c) IV > II > III >V>I
(d) III > II > IV>V>I​

Answer 1

Answer:

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Explanation:

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