Question

11. Diagram of the adjacent picture frame has outer dimensions = 24 cm x 28 cm
and inner dimensions 16 cm x 20 cm. Find the area of each section of
the frame, if the width of each section is same.
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Answer 1

Answer:

96cm^2, 80cm^2, 96cm^2, 80cm^2

Step-by-step explanation:

width of frame = 28-20/2=4cm

area of trapezium=1/2 × h ( a+ b )

here , height =width

area of trapezium 1 = area of trapezium 2

1/2× 4(20+28) = 2×48= 96cm^2

area of trapezium 3=area of trapezium 4

1/2 × 4( 24+16)= 2× 40= 80cm^2

area of rectangle = L×B

L= 20cm

B= 16cm

20×16=320cm^2