Question

11. Divide ₹ 200 into two parts such that 1/3 of the first and1/2 of the second are equal (solve in one variable)
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Answer 1

Answer:

120₹ and 80₹

Step-by-step explanation:

Let the partition be x

Other part =200-x

As per Question,

x/3=(200-x)/2

x/3+x/2=100

5x/6=100 =>. x/6=20

X=6×20= ₹120 (first part)

200-120= ₹80 (Second part)