Question

11. Each of equal sides of an isosceles triangle is
4 cm greater than its height. If the base of the
triangle is 24 cm; calculate the perimeter and
the area of the triangle.​

Answer 1

Answer:

24 को 4 बराबर 66 x 4 = 24 से विभाजित किया गया है और यही उत्तर है जब आपको इस k के लिए समानांतर रेखाओं का उपयोग करना होगा

24 ko 4 baraabar 66 x 4 = 24 se vibhaajit kiya gaya hai aur yahee uttar hai jab aapako is k ke lie samaanaantar rekhaon ka upayog karana hoga

Step-by-step explanation:

Answer 2

Answer:

Perimeter = 64cm

Area = 192cm^2

Step-by-step explanation:

Base = 24cm

Height = xcm

(x+4)^2 = x^2 + (12)^2

x^2 + 8x + 16 = x^2 + (12)^2

8x = x^2 - x^2 + 144 - 16

8x = 128

x = 128/8

x = 16

Perimeter = 24 + 16+ 4 + 16 + 4

Perimeter = 64cm

Area = $\sqrt{s(s-a)(s-b)(s-c)}$

{S = 64/2 = 32 ; A = 24 ; B = 20 ; C = 20}

Area = $\sqrt{32(32-24)(32-20)(32-20)}$

Area = $\sqrt{32*8*12*12}$

Area = $\sqrt{8*4*8*12*12}$

Area = 8*2*12

Area = $192cm^{2}$