Question

11. Express the following sets using ordered pairs.
a) {x/x ϵN and 17 b) {x/x ϵN and 100≤x<400}

Answer 1

Answer:

N=100

Hence the median class =

2

N

=

2

100

=50

In the above table 12−14 is the median class and the respective cf is 20 (nearest to the value of 50)

According to the question:

l

1

=12 (lower limit of median class)

cf=48 (cf= cumulative frequency preceding the median class)

i=l

2

−l

1

=2 (width of class interval of median class)

f=15 (frequency of median class)

Median=l

1

+

f

2

N

−C

×i=12+

15

50−48

×2

Median=12.266