Question

11. Figure 1 shows a paper kite ABCD in which BD = 51 cm,
AC = 34 cm, AC I BD and AO = OC. Find the cost of manufacturing
it at the rate of 0.05 per cm.
12. Find the area of a quadrant of a circle whose circumference is 22 cm.​

Answer 1

Answer:

Cost of manufacturing =  Rs  43.35  ,  a paper kite ABCD in which BD=51,AC=34cm,AC is perpendicular to BD and AO=OC

Step-by-step explanation:

BD = 51 cm

AC = 34

AO = OC = AC/2 = 34/2 = 17 cm

AC ⊥ BD

area of ΔABD

= (1/2) BD * AO

= (1/2) * 51 * 17

Area of ΔCBD

= (1/2)BD * CO

= (1/2) * 51 * 17

Area of ABCD Kite = (1/2) * 51 * 17 + (1/2) * 51 * 17

= 51 * 17

= 867 cm²

cost of manufacturing in at the rate of ₹0.05 per cm²  = 867 * 0.05

= 43.35 Rs