Question

11. Find a quadratic polynomial whose zeroes are 1 and -3.
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Answer 1

Answer:

formula is : x2 _( alpha plus beeta)x _ alpha × beeta substituting values you get answer ok

Answer 2

Answer:

✮ x^2+2x -3 ✮

Step-by-step explanation:

Given

Zeros of the polynomial is 1 and -3 ( α = 1 β = -3 )

To be find

Find a quadratic polynomial whose zeroes are 1 and -3.

☛ Solution

formula to find out it

☛ x^2-(α+β)x +(αβ)

put it to find out

• ☛ x^2-(1-3)x + (1 x -3)
• ☛ x^2-(-2)x + ( -3)
• ☛ x^2+2x-3

Hence answer will be ☛ x^2+2x-3