Question

11. Find:
(i) angle DBC
(ii) angle BDC
(iii) angle DBA
(iv) angle A​

Answer 1

Answer:

angle DBC=65(alternatively interior)

65+50+BDC=180

BDC=65

DBA=65(alternatively interior)

A+65+65=180

A=50

Answer 2

1 angle DBC=65degree

by alternate interior angle

2 angle BDC=65

sum of interior angles of a triangle =180

in triangle DBC

65 + 50 + BDC = 180

BDC = 180 - 115

BDC= 65

3 DBA = 65

by alternate interior angle

4 angle A = 55

65 + 65 + A = 180

A = 55