11. Find the area of a triangle in which a=10 cm, b = 18 cm c=14 cm
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Answer:
Given sides are 18cm,10cm and 14cm
Area of triangle =
s(s−a)(s−b)(s−c)
⇒a=18cm,b=10cm and c=14cm
⇒s=
2
a+b+c
=
2
18+10+14
=
2
42
=21cm
Area =
21(21−18)(21−10)(21−14)
=
21×3×11×7
=21
11
sqcm
Hence, the answer is 21
11
sqcm.
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