Math, asked by sjspark, 1 year ago

11. Find the centered of A ABC whose vertices are A (-3,0) B (5,-2) and C (-8,5)

Answers

Answered by sejal3108
3

Answer:

X= (x1 + x2 + x3)/3

X=-3+5-8/3

X=-6/3

X=-2

Y=(y1+y2+y3)/3

Y=0-2+5/3

Y=3/3

Y=1

(X,Y)=(-2,1)

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