Math, asked by jayshreekmohite05, 3 months ago

(11) Find the compound
interest if Principle = 2000 R:
Rate of interest = 5 pcpca,
Duration = 2 years.​

Answers

Answered by Anonymous
14

Answer :-

Given :-

  • Principal = Rs. 2000
  • Rate of interest = 5% p.c.p.a
  • Time = 2 years

To Find :-

  • Compound interest

Solution :-

We know that,

\implies\sf A = P \left( 1 + \dfrac{R}{100}\right)^n

Substituting the values in formula :-

\implies\sf A = 2000 \times \left( 1 + \dfrac{5}{100}\right)^2

\implies\sf A = 2000 \times \left( 1 + \dfrac{1}{20}\right)^2

\implies\sf A = 2000 \times \left(\dfrac{21}{20}\right)^2

\implies\sf A = \not2\not0\not0 \: 0 \times \dfrac{21 \times 21}{\not{2}\not0\times 2\not0}

\implies\sf A = \dfrac{10 \times 21 \times 21}{2}

\implies\sf A = 5 \times 21 \times 21

\implies\sf A = 2205

Now, we have amount and principal. We know that,

Compound interest = Amount - Principal

= 2205 - 2000

= 205

Compound interest = Rs. 205

Answered by Anonymous
134

A N S W E R :

  • The Compound Interest is Rs. 205.

Given :

  • Principal = 2000

  • Rate = 5%

  • Duration = 2 Years

To find :

  • Find the Compound Interest ?

Solution :

As we know that,

Formula Used :

★ Compound Interest = P(1 + i)^t - P

So,

  • P is the principal

  • i is the interest rate in decimal

  • t is the number of years

Substituting the values,

=> C.l = 2000(1 + 0.05)^2 - 2000

=> C.l = 2000(1.05)^2 - 2000

=> C.I = 2000 × 1.1025 - 2000

=> C.I = 2205 - 2000

=> C.l = 205

Hence,

  • The Compound Interest is Rs. 205.
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