11. Find the equation of the hyperbola in standard form with eccentricity 2 and distance between
whose fociis 16.
A) x2-y = 16 B) x2 - y2 = 32 c) x² - y2 = 64 d) none of these
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Answer:
Answer
Vertices(±5,0)Foci(±7,0)
a=±5 and ae=±7
And e=
5
7
We know e=
1+
a
2
b
2
On squaring both sides we get:
e
2
=1+
a
2
b
2
Or
25
49
=1+
25
b
2
Or
25
b
2
=
25
24
b
2
=24
The equation of hyperbola is
25
x
2
−
24
y
2
=1
24x
2
−25y
2
=600
Hence, Option [A] and [C] are correct.
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