11. Find the equation of the straight line whose x and y-intercepts on the axes are given by
(i) 2 and 3 (ii) 3
1 - and 2
3 (iii) 5
2 and 4
3
Answers
Answered by
0
In the attachments I have answered this problem.
Formula :
The equation of line in intercept form is
x/a + y/b = 1
See the attachments for detailed solution.
Formula :
The equation of line in intercept form is
x/a + y/b = 1
See the attachments for detailed solution.
Attachments:
Answered by
0
Solution :
****************************************
Equation of the line whose
x-intercept = a , y-intercept = b,
x/a + y/b = 1
*****************************************
i ) Given , a = 2 , b = 3
Required equation ,
x/2 + y/3 = 1
=> ( 3x + 2y )/6 = 1
=> 3x + 2y = 6
ii ) Given a = -1/3 and b = 2/3 ,
x/(-1/3) + y/(2/3) = 1
=> -3x + 3y/2 = 1
=> ( -6x + 3y ) /2 = 1
=> -6x + 3y = 2
iii ) Given a = 5/2 , b = 4/3
x/(5/2) + y/(4/3) = 1
=> 2x/5 + 3y/4 = 1
=> ( 8x + 15y )/20 = 1
=> 8x + 15y = 20
••••
****************************************
Equation of the line whose
x-intercept = a , y-intercept = b,
x/a + y/b = 1
*****************************************
i ) Given , a = 2 , b = 3
Required equation ,
x/2 + y/3 = 1
=> ( 3x + 2y )/6 = 1
=> 3x + 2y = 6
ii ) Given a = -1/3 and b = 2/3 ,
x/(-1/3) + y/(2/3) = 1
=> -3x + 3y/2 = 1
=> ( -6x + 3y ) /2 = 1
=> -6x + 3y = 2
iii ) Given a = 5/2 , b = 4/3
x/(5/2) + y/(4/3) = 1
=> 2x/5 + 3y/4 = 1
=> ( 8x + 15y )/20 = 1
=> 8x + 15y = 20
••••
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