Math, asked by kiranprajapati1134, 4 months ago

11. Find the LCM of the following:
(ii) 8, 10 and 12​

Answers

Answered by raghuramansbi
4

Answer:

\huge{\underline{\mathtt{\red{❥A}\pink{N}\green{S}\blue{W}\purple{E}\orange{R}}}}

Find the LCM of the following:

(ii) 8, 10 and 12

THE LCM OF THE FOLLOWING IS 120

Answered by MSRKN404
6

Answer:

Problem & Workout :

Problem & Workout :step 1 Address input parameters & values.

Problem & Workout :step 1 Address input parameters & values.Integers: 8 10 12

Problem & Workout :step 1 Address input parameters & values.Integers: 8 10 12lcm (8, 10, 12) = ?

Problem & Workout :step 1 Address input parameters & values.Integers: 8 10 12lcm (8, 10, 12) = ?step 2 Arrange the group of numbers in the horizontal form with space or comma separated format

Problem & Workout :step 1 Address input parameters & values.Integers: 8 10 12lcm (8, 10, 12) = ?step 2 Arrange the group of numbers in the horizontal form with space or comma separated format8, 10 and 12

Problem & Workout :step 1 Address input parameters & values.Integers: 8 10 12lcm (8, 10, 12) = ?step 2 Arrange the group of numbers in the horizontal form with space or comma separated format8, 10 and 12step 3 Choose the divisor which divides each or most of the integers of in the group (8, 10 and 12), divide each integers separately and write down the quotient in the next line right under the respective integers. Bring down the integer to the next line if the integer is not divisible by the divisor. Repeat the same process until all the integers are brought to 1.

Problem & Workout :step 1 Address input parameters & values.Integers: 8 10 12lcm (8, 10, 12) = ?step 2 Arrange the group of numbers in the horizontal form with space or comma separated format8, 10 and 12step 3 Choose the divisor which divides each or most of the integers of in the group (8, 10 and 12), divide each integers separately and write down the quotient in the next line right under the respective integers. Bring down the integer to the next line if the integer is not divisible by the divisor. Repeat the same process until all the integers are brought to 1.LCM of 8, 10 and 12

step 4 Multiply the divisors to find the lcm of 8, 10 and 12

step 4 Multiply the divisors to find the lcm of 8, 10 and 122 x 2 x 5 x 3 x 2 = 120

step 4 Multiply the divisors to find the lcm of 8, 10 and 122 x 2 x 5 x 3 x 2 = 120LCM(8, 10, 12) = 120

step 4 Multiply the divisors to find the lcm of 8, 10 and 122 x 2 x 5 x 3 x 2 = 120LCM(8, 10, 12) = 120The least common multiple for three numbers 8, 10 and 12 is 120

Similar questions