Math, asked by raunak30311, 8 days ago

11. Find the least number which must be subtracted from 6156 to make it a perfect square ​

Answers

Answered by pandeypushpa9603
2

Answer:

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Answered by chandan454380
0

Answer:

At least 72 must be subtracted from 6156 to make it a perfect square ​

Step-by-step explanation:

First we have to find the square root of 6156:

\sqrt{6156}=2×3×3× \sqrt{19}  

=18×4.358=78.444...

Now, we find the square of 78 as follows:

78 ^2=78 \cdot 78=6084

Let us now subtract 6156 from 6084 as shown below:

  6156-6084=72

Hence, 72 will be subtracted from 6156 to make it a perfect square.

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