Question

11. Find the magnitude of an angle, which is ⅔of its supplement​

Answer 1

Answer:

We will first find the magnitude of an angle which is 23 of its supplement.

Let the magnitude of this angle be x∘ . As per the definition of supplementary angles, the supplement of this angle will be (180−x)∘ .

I.We are given that the magnitude of the angle is 23 of its supplement.

⇒x=23(180−x)⇒3x=360−2x⇒3x+2x=360⇒5x=360⇒x=3605⇒x=72

Thus, our first answer is: the magnitude of the angle which is 23 of its supplement is 72∘ .

So, the correct answer is “ 72∘ ”.

II.Now we will find the magnitude of an angle which is 14 of its complement.

Let the magnitude of this angle be x∘ . As per the definition of complementary angles, the complement of this angle will be (90−x)∘ .

We are given that the magnitude of the angle is 14 of its complement.

⇒x=14(90−x)⇒4x=90−x⇒4x+x=90⇒5x=90⇒x=905⇒x=18

Thus, our first answer is: the magnitude of the angle which is 14 of its complement is 18∘ .

So, the correct answer is “ 18∘ ”.

Step-by-step explanation:

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Answer 2

Answer:

72 °

Step-by-step explanation:

consider an angle as x

Now,

x + 2x/3= 180

5x       =180*3

x         = 108

therefore required angle= 180-x

                                         = 72 °