Question

(11) Find the number of natural numbers between 101 and 999 which are divisible by
both 2 and 5.
​

Answer 1

Answer:

89

Step-by-step explanation:

To find no. of multiples of 2 and 5 both, we find no . of multiples of LCM(2,5)

that is 10

we form AP

110,120,130..990

a= 110

d= 10

L=990

L= a +( n-1)d

990 =110 +(n-1)10

880 = (n-1)10

n-1 = 88

n = 89

Answer 2

Answer:

Step-by-step explanation:

Numbers which are divisible by 2 and 5 both is only 10

So the numbers which end 0 like 110,120,130,140........970,980,990

Are the numbers which arr divisible by 2 and 5 both between 101 and 999