Question

11 Find the probability that a number selected at random from the numbers 1, 2, 3, ......., 35 is

a prime number​

Answer 1

Answer:

Total no. of possible outcomes = 35 {1, 2, 3, …. 35} (i) E ⟶ event of getting a prime no. No. of favourable outcomes = 11 {2, 3, 5, 7, 11, 13, 17, 19, 23, 29, 31} Probability, P(E) = (No.of favorable outcomes)/(Total no.of possible outcomes) = 11/35

Step-by-step explanation:

Total no. of possible outcomes = 35 {1, 2, 3, …. 35} (i) E ⟶ event of getting a prime no. No. of favourable outcomes = 11 {2, 3, 5, 7, 11, 13, 17, 19, 23, 29, 31} Probability, P(E) = (No.of favorable outcomes)/(Total no.of possible outcomes) = 11/35 (ii) E ⟶ event of getting no. which is multiple of 7 No. of favourable outcomes = 5 {7, 14, 21, 28, 35} P(E) = 5/35 = 1/7 (iii) E ⟶ event of getting no which is multiple of 3 or 5 No. of favourable outcomes = 16 {3, 6, 9, 12, 15, 18, 21, 24, 27, 30, 33, 5, 10, 20, 25, 35} P(E) = 16/35