Question

11. Find the smallest number that may be subtracted from 6,986 so that the number may
become:
a) divisible by 3
b) divisible by 10​

Answer 1

Answer:

a 2

b 86

Step-by-step explanation:

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Answer 2

Answer:

a)2

b)6

Step-by-step explanation:

a) if we divide 6986 with 3 , we get 2 as remainder . so we have to subtract 2 from 6986 which will give us 6984 now if we divide 6984 by 3 , we will get 2328 which is an integer(means 6984 is exactly divisible by 3)

b) of we divide 6986 by 10, we get 6 as remainder . so we have to subtract 6 from 6986 which will give us 6980 . now if we divide 6980 by 10 , we get 698 which is an integer( means 6980 is exactly divisible by 10)