Question

11. Find the smallest number which when
divided by 14, 21 and 35 leaves a remain-
der 12, 19 and 33 respectively.
Solution :​

Answer 1

Answer:

Here is the correct solution.....

Step-by-step explanation:

Let us find LCM of 14, 21,35.

The LCM is 210.

When 210 is divided by 14, we get Zero Remainder.If we deduct 2 from 210, we get 208, which on dividing by 14 gives remainder of 12. Again when 210 is divided by 21,

remainder is zero. When 208. is divided by 21, remainder is 19. Similarly for 45.

Hence the no is 208

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Answer 2

Step-by-step explanation:

14 2x 7

21 3x7

35 5x 7

LCM(14, 21, 35) 7 x 2x3x 5 = 210

when divided by 14, 21 and 35 leaves remainder 12, 19

and 33.

means 2 less than the divisor.

Hence the smallest number = 210 -2 208