11. Find the sum of first n even natural number
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0+1+2+3+4+5+6+7+8+9 =45
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Answer:
First n even natural numbers: 2,4,6,8,10,,n
Here, a=2,d=4−2=2
Sum =S
n
=
2
n
[2a+(n−1)d]
=S
n
=
2
n
[2(2)+(n−1)2]
=n(n+1).
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