Question

11. Find the sum of squares of first 35 natural numbers.
(a) 14910
(b) 15510
(c) 14510
(d) 16510​

Answer 1

Answer:

Correct Option: A. Sum of the square of first n natural numbers = n(n+1)(2n+1) / 6. Given n = 35 ∴ Required sum = ( 35 x 36 x 71 ) / 6 = 14910. Previous Question

Answer 2

Answer:

a=1

d=1

an=35²

n=35²

s=n/2(2a+(n-1) d)

s=35²/2(1+35)

s=14910

answer is option A