Question

11. Find the sum of the LCM and HCF of 1152 and 1664.
12. Find the smallest sumber which when divided by 8, 12, 16, 24, and 36 leaves ne reminder​

Answer 1

1. LCM of 1152 and 1664 is 14976.

  HCF of 1152 and 1664 is 128.

  14976 + 128 = 15104

2. Here the answer is 2 (if you are not counting 1 here).

Hope it helps.

Answer 2

Answer:

11. LCM = 118144 and HCF = 128

12. 4 is the smallest number which leaves remainder 0

Step-by-step explanation:

11. LCM of

1152 = 2*2*2*2*71

1664 = 2*2*2*2*2*2*2*13

by multiplying all we get,

118144

HCF of 1152 and 1664 is

a = bq+ r

1664 = 1152 × 1 + 512

1152 = 512 × 2 + 128

512 = 128 × 4 + 0

therefore HCF = 128

12. if we take HCF of all the numbers we get 4 as the HCF