Question

11) Find the value of k, if the roots of the quadratic equation 2x² - 6x + k = 0 are real
and equal​

Answer 1

Answer:

9/2

Step-by-step explanation:

The roots of the quadratic equation are real and equal.

∴ b² - 4ac = 0

(-6)² - 4 × 2 × k = 0

- 8k = -36

k = 9 / 2

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Answer 2

Step-by-step explanation:

p(X)=2x^2-6x+k

d=b^2-4ac

=-6^2-8k

=36-8k

therefore,8k=-36

k=9/2