11) Find the value of the polynomial 2x² − x³ + x + 2 at x = 1 *
2 points
- 4
5
3
4
12) Find the value of 'k' , if x - 1 is a factor of p(x) = kx² + 3x + k *
2 points
- 3
- 2
-3/2
3/2
13) Factorise : 2x² + x − 15 *
2 points
(x+5) (x-3)
(x + 3) (2x - 5)
(x+3) (x-5)
(2x + 3) (x-5)
14) Show that 0.3333..... can be expressed in the form p/q, where p and q are integers and q ≠ 0. *
2 points
3
-3
-1/3
1/3
15) Expand ( 2a − 3b + c)² *
2 points
4a² + 9b² + c² − 12ab − 6bc + 4ac
4a² + 9b² - c² − 12ab − 6bc + 4ac
4a² + 9b² + c² − 12ab + 6bc + 4ac
4a² + 9b² + c² + 12ab + 6bc + 4ac
16) On plotting the points O(0,0) , A(3,0), B(3,4), C(0,4) and joining OA, AB, BC, and CO which of the following figure is obtained? *
3 points
Square
Rectangle
Trapezium
Rhombus
17) Simplify ( √7 + √5 ) ( √7 - √5 ) *
3 points
-2
12
2
4
18) Factorise: y³ − 3y² − 9y − 5 *
4 points
(x+1) (x-1) (x-5)
(y+1) (y+1) (y-5)
(y-1) (y+1) (y+5)
(y+1)(y-5)
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Answer:
\pink{\bold{\underline{ ✪ UPSC-ASPIRANT✪ }}}✪UPSC−ASPIRANT✪
\red{\bold{\underline{\underline{QUESTION:-}}}}QUESTION:−
Q:-
if \: c = \frac{a}{b} - \frac{d - e}{f - d}ifc=ba−f−dd−e
Find the value of f when a=3,b=4,c=-6,d=-5 & e=2
\huge\tt\underline\blue{Answer }Answer
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⟹ - 6 = \frac{3}{4} - \frac{( - 5) - 2}{f - ( - 5)}⟹−6=43−f−(−5)(−5)−2
⟹ - 6 = \frac{3}{4} - \frac{( -7)}{f + 5}⟹−6=43−f+5(−7)
⟹ - 6 = \frac{3}{4} + \frac{7}{f + 5}⟹−6=43+f+57
⟹ - 6 - \frac{3}{4} = \frac{7}{f + 5}⟹−6−43=f+57
⟹ \frac{ - 24 - 3}{4} = \frac{7}{f + 5}⟹4−24−3=f+57
⟹ - \frac{27}{4} = \frac{7}{f + 5}⟹−427=f+57
⟹ - 27(f + 5) = 28⟹−27(f+5)=28
⟹ - 27f - 135 = 28⟹−27f−135=28
⟹ - 27f = 28 + 135⟹−27f=28+135
⟹ - 27f = 163⟹−27f=163
- ⟹f = \frac{163}{ - 27}⟹f=−27163
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