Question

11. Find the zeroes of the following polynomials:
(1) 2x^2 + 7x + 3 (ii) 3x^2 - x - 4.​

Answer 1

Answer:

refer below

Step-by-step explanation:

2x2+7x+3

= 2x^2 + 6x + x + 3      = 0

= 2x(x+3) + 1(x+3)                =0                      

(x+3) (2x+1)                   =0

x = -3    , -1/2

3x2-x-4

= 3x2-4x+3x-4             =0

x(3x-4) + 1 (3x-4)                  =0

(3x-4) (x+1)                       =0

x = 4/3 , -1                   =0

MARK AS BRANLIEST