Question

11. Find the zeroes of the Quadratic Polynomial x2 - 2x - 8.​

Answer 1

x² - 2x - 8 = 0

x² - 4x + 2x -8 = 0

x ( x - 4) + 2 ( x - 4) = 0

( x + 2 )( x - 4 ) = 0

x = -2,4

HOPE THIS HELPS ♥️

Answer 2

Answer:

=>x^2-2x-8

=>x^2-4x+2x-8

=>x(x-4)+2(x-4)

=>(x+2)(x-4)

=>x=4,-2